sl-atl
10/12/2009, 05:37 PM
I'm pretty sure that I have monti eating nudibranchs, again, so I've resolved to kill them before they kill my corals and gotten some lab grade KMnO4, but, am not 100% sure how to proceed from there...
Based on on Eric Borneman's article, I would want a dip with 50mg/l. Now, I have a lab grade powder that I assume is 100% pure. I guess I'll make 1l of the solution, so...
C1V1=C2V2
where C2=50mg/L
and V2=1L
C1V1=50mg
Does that mean that I would simply add 50mg of the pure substance to a 1l of water? That seems a little too easy, especially since I less than aced Chem 101. - but give me a break I was an EE. ;)
Now if I got that far correctly, since I don't have a balance I would need to convert from mass to volume. Assuming 2.703 g/mL for KMnO4:
0.050g /2.703g/ml = 0.0185ml
So... I would add 0.0185ml of the powder to a liter of seawater. (?)
I'd really appreciate somebody checking my work before I start dipping a couple hundred dollars worth of corals!
Thanks,
Stuart
Based on on Eric Borneman's article, I would want a dip with 50mg/l. Now, I have a lab grade powder that I assume is 100% pure. I guess I'll make 1l of the solution, so...
C1V1=C2V2
where C2=50mg/L
and V2=1L
C1V1=50mg
Does that mean that I would simply add 50mg of the pure substance to a 1l of water? That seems a little too easy, especially since I less than aced Chem 101. - but give me a break I was an EE. ;)
Now if I got that far correctly, since I don't have a balance I would need to convert from mass to volume. Assuming 2.703 g/mL for KMnO4:
0.050g /2.703g/ml = 0.0185ml
So... I would add 0.0185ml of the powder to a liter of seawater. (?)
I'd really appreciate somebody checking my work before I start dipping a couple hundred dollars worth of corals!
Thanks,
Stuart