View Full Version : Replacement LED driver/ power supply....where to find this one?
ptreef
08/18/2015, 08:00 AM
So I have basically the evergrow, reefbreeders style full spectrum led.
Came from AJE reef led, who is no longer in business.
One of the drivers died. It was for the color led's
If I swap it the colors work and blue's don't so it the driver.
Anyway, can't seem to find a replacemenmt.
Idea what will work? vs buy a whole new light.
Thanks,
http://i222.photobucket.com/albums/dd71/steveh1234/IMAG0065_zpsoyrkfjoi.jpg
colorful1180
08/18/2015, 09:23 AM
I got one of the driver from manufacturer (https://www.facebook.com/jack.xu.3388),where did you buy the light?you can ask for a new driver from vendor as warranty support.
ptreef
08/18/2015, 11:31 AM
got it from AJM reef led....of which is out of business.
these are all generic china made systems.
Can't seem to pinpoint the driver anywhere.
AZRippster
08/18/2015, 03:57 PM
Did you try googling that part number on the driver? It may give you at least a clue where to look.
mcgyvr
08/18/2015, 04:03 PM
First "good" one I found..
Meanwell HLG-60H-C700A
Just google 100V 70W LED driver
Please be careful.. LED drivers and anything really without output voltages above 48-60VDC are dangerous..
ptreef
08/18/2015, 07:21 PM
Did you try googling that part number on the driver? It may give you at least a clue where to look.
Yup I tried googling everything on it and nothing....
ptreef
08/18/2015, 07:23 PM
First "good" one I found..
Meanwell HLG-60H-C700A
Just google 100V 70W LED driver
Please be careful.. LED drivers and anything really without output voltages above 48-60VDC are dangerous..
So the current driver has power leads and a 4 pin output?
How would I know what wires go where?
AZRippster
08/18/2015, 08:31 PM
You're going to need a multimeter. With that, as long as the other working driver has the same label, you can test to see at max what it's output may be. You will also be able to determine + and - lines.
vBulletin® v3.8.4, Copyright ©2000-2024, Jelsoft Enterprises Ltd.