Deflection Calculator
I am looking for a way to calculate the deflection of different size pieces of angle iron.
Anybody have a link to a website where I can plug in some values, or maybe just the formulas. I am looking at 72" of angle iron, either 1-1/2x1-1/2x3/16 or 2x2x1/8 Thanks |
I am getting close, but I still need some more info and help.
Quote:
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That would have been my advice (look in machinery's handbook).
I will see what I can dig up steve. |
I may have that, but I'll have to dig the book out- Give me a few hours
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2x2x1/8 has an I of 0.189 in^4. Not sure if you can read it in the picture but 2x2x1/8 is the last line. This is from the Manual of Steel Construction by the American Institute of Steel Construction
http://i215.photobucket.com/albums/c...b/100_4411.jpg |
you guys make my brain hurt lol
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I also found this, it's the general equation for moment of inertia for angle iron
http://i215.photobucket.com/albums/c...b/100_4417.jpg |
I've used these tools.
I suspect you need to use uniform loading. http://www.engineersedge.com/beam_be...m_bending1.htm |
But you still need the moment of Inertia for the material that you wish to model :)
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Correct!
The chart posted is the same one I have. It has data for one of the two sizes I want to compare. But not the 1-1/2x1-1/2x3/16. |
If you have something smaller than a L2x2x?. Then you'll have to use the equations posted above. You'll want to use the equation for Ix.
Given that...an angle isn't the best thing to use for a beam, and 72" is pretty dang far for a 1 1/2" angle. |
I am constructing a plywood tank that will have two sides glass. I am going to have a angle iron eurobrace around the top.
I am only slightly worried about the deflection because the glass will be 5/8 or 3/4. It is mainly to re-enforce the corner. |
If that's the case, you can easliy calculate the Ix from the equations above (or Iy, since it should be the same for an equal leg angle) and use (5wl^4)/(384EI) as your deflection calc. The force on the top will be minimal because you have a triangular load on the glass. Should be fine.
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You might need to dumb it down a little fore me.
What are the w and l? I still don't have the I for the 1-1/2 angle. |
w is the loading on the piece that you want to calculate the deflection for (lbs/ft), l is the length of the piece you want to calculate the deflection for. you would need to calculate I for the 1-1/2 angle (it looks like it is 0.111, if I did my math right) or you could use the 2x2 angle since you know the value of I for that one.
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as said above, "w" is in pounds per inch, "l" is the length of the member in inches, E is the modulus of elasticity (29 x 10^6 for steel) and I is the moment of inertia which is calculated above (as I said before, use the equation for Ix). Make sure the calculation for Ix the units come out as inches^4.
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So...
W=10 10 bs/inch along the length of the angle. I=72 Length of angle E=29,000,000 I=.190 Ix And the equation (5wl^4)/(384EI) (5*10*72^4)/(384*29,000,000*.190) would result in .635 inches of deflection. Now, I need the vales for the 1-1/2 angle, as I can't see how to derive x or y for the center of gravity. |
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