So...
W=10 10 bs/inch along the length of the angle.
I=72 Length of angle
E=29,000,000
I=.190 Ix
And the equation (5wl^4)/(384EI)
(5*10*72^4)/(384*29,000,000*.190) would result in .635 inches of deflection.
Now, I need the vales for the 1-1/2 angle, as I can't see how to derive x or y for the center of gravity.
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Current Tank Info: 220g custom plywood. SPS heavy with Sequence Hammerhead return with 4-Way OM. Tunze 6100, 6200 and Wavebox. 5000btu DIY Chiller. Lighting is 10K mh 250W / VHO Actinic Skimer - H&S A200-2x1260
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