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Unread 07/29/2008, 05:09 PM   #17
AcroSteve
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Join Date: Feb 2003
Location: Electric Avenue
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So...

W=10 10 bs/inch along the length of the angle.
I=72 Length of angle
E=29,000,000
I=.190 Ix

And the equation (5wl^4)/(384EI)
(5*10*72^4)/(384*29,000,000*.190) would result in .635 inches of deflection.

Now, I need the vales for the 1-1/2 angle, as I can't see how to derive x or y for the center of gravity.


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